How to find a plane parallel to a given plane?

I have a plane with equation 4x-3y+z=10, how do I find the equation for a plane that is parallel and 4 units away from this given plane? I know I can use the normal vector for the first plane (4,-3,1) for the second plane, but I need a point on the second plane in order to form an equation. How do I find that point?|||4x - 3y + z = k is a plane parallel to the plane 4x - 3y + z = 10


Distance between them is


l 10 - k l / 鈭歔(4)^2 + (3)^2 + (1)^2] = 4


=%26gt; l 10 - k l = 4鈭?26)


=%26gt; 10 - k = 卤 4鈭?26)


=%26gt; k = 10 卤 4鈭?26)


=%26gt; equations of plane parallel to the given plane at a distance of 4 units are


4x - 3y + z = 4鈭?26) and


4x - 3y + z = - 4鈭?26)